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Let ABC be a triangle right at C. The va...

Let `ABC` be a triangle right at `C.` The value of `(log_(b+c)a+log_(c-b)a)/(log_(b+c)a*log_(c-b)a)(b+c!=1, c-b!=1)` equals

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Let ABC be a triangle right at C. The value (log_(b+c)a+log_(c-b)a)/(log_(b+c)a*log_(c-b)a)(b+c!=1,c-b!=1) equals

a^(log_(b)c)=c^(log_(b)a)

(1+log_(c)a)log_(a)x*log_(b)c=log_(b)x log_(a)x

the value of a^(log((b)/(c)))*b^(log((c)/(a)))c^(log((a)/(b)))

Show that log_(b)a log_(c)b log_(a)c=1