[" 59.Two blocks of mass "m_(1)=6kg],[" and "m_(2)=3kg" are as shown in "],[" the diagram.Coefficient of fric- "],[" tion between.Coefficient of fric- "],[" tween "m_(1)" and the surface is "0.5(1)/(1)" force that "],[" can be applied to the mass "m_(1)" so that they move without "],[" separation is "],[[" (1) "41N," (2) "61N],[" (3) "81N," (4) "101N]]

Two blocks of mass m_(1) = 6 kg and m_(2) = 3kg are as shown in the diagram. Coefficient of friction between m_(1) and m_(2) and between m_(1) and m_(2) and between m_(1) and the surface is 0.5 and 0.4 , respectively . The maximum horizontal force that can be applied to the mass m_(1) so that they move without separation is

Two blocks of masses m_(1) and m_(2) are connected by a spring of stiffness k. The coefficient of friction between the blocks and the surface is mu . Find the minimum constant force F to be applied to m_(1) in order to just slide the mass m_(2) .

Two blocks of masses m_(1) and m_(2) are connected by a spring of stiffness k. The coefficient of friction between the blocks and the surface is mu . Find the minimum constant force F to be applied to m_(1) in order to just slide the mass m_(2) .

Two blocks a and B of mass m_(A)=1kg and m_(B)=3kg are kept on the table as shown in figure the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2 the maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is [Take g=10m//s^(2) ]

Two blocks A and B of masses m_(A) = 1kg and m_(B) = 3kg are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is ________ (in N): [Take g = 10 m//s^(2) ]

Two blocks M and m are arranged as shown in the diagram The coefficient of friction between the block is mu_(1) = 0.25 and between the ground and M is mu_(2) = (1)/(3) If M = 8 kg then find the value of m so that the system will remain at rest

Two blocks M and m are arranged as shown in the diagram The coefficient of friction between the block is mu_(1) = 0.25 and between the ground and M is mu_(2) = (1)/(3) If M = 8 kg then find the value of m so that the system will remain at rest

Two block of masses m_(1) and m_(2) connected by a light spring rest on a horizontal plane. The coefficient of friction between the block and the surface is equal to mu . What minimum constant force has to be applied in the horizontal direction to the block of mass m_(1) in order to shift the other block?

Two blocks m_(1)=1kg , m_(2)=2kg are placed one upon the other. m_(1) is kept on m_(2) . The force of static friction between m_(1) and m_(2) is 0.2 and between m_(2) and the horizontal surface and the floor is 0.28 . Calculate the maximum force that can be applied on m_(2) so that m_(1) and m_(2) does not get separated. (g=10ms^(-2))