[" Wation (where sgn represent signum function) "],[" (ii) "sgn(x^(2)-1)=(x+1)^(2)]

Find the number of solution of equation (where sgn represent signum function) (i) sgn (x)=|x| (ii) sgn(x^(2)-1)=(x+1)^(2)

Find the number of solutions of equation (where sgn represent signum function) sgn (x)=|x| .

If the value of of the integral I=int_(0)^(2pi)sgn(e^(x))dx is equal to kpi , then the smallest prime number greatest than 2k is (where, sgn (x) represents the signum functiono f x)

If the value of of the integral I=int_(0)^(2pi)sgn(e^(x))dx is equal to kpi , then the smallest prime number greatest than 2k is (where, sgn (x) represents the signum functiono f x)

The number of integral values of x satisfying the equation sgnis greatest integer function,sgn{[(15)/(1+x^(2))])=[1+(2x)] (where [.] is greatest integer function [.] fractional part function and sgn(x) is dignum function)

Let f(x)=2tan^(3)x-6tan^(2)x+1+sgn(e^(x)),AA x in [-(pi)/(4),(pi)/(4)], Then the positive difference between the least value and the local maximum value of the function is (where sgn (f(x)) represents the signum function)

Let f(x)=g(x)sgn(x^(3)+6x^(2)+11x+6) where sgn denotes signum function and f(x)=ax^(3)+x^(2)+x+1, then minimum number of points of discontinuity of the function f(x) is

Let f:R^(+)rarr{-1,0,1} defined by f(x)=sgn(x-x^(4)+x^(7)-x^(8)-1) where sgn denotes signum function then f(x) is (1) many- one and onto (2) many-one and into one-one and onto (4) one- one and into

Let f : R^+ ->{-1, 0, 1} defined by f(x) = sgn(x-x^4 + x^7-x^8-1) where sgn denotes signum function then f(x) is (1) many- one and onto (2) many-one and into (3) one-one and onto (4) one- one and into