`int_1^2(dx)/(x(1+2x)^2)`

int_1^2 (dx)/(x(1+x^2))

(i) int_1^2 (dx)/((x+1)(x+2)) (ii) int_1^2 (x+3)/(x(x+2) dx

Let I = int_1^2 (dx)/(sqrt(1 + x^2)), J = int_1^2 (dx)/(x) , then

int_0^(1//2)(dx)/((1+x^2)sqrt(1-x^2)) is equal to

int_1^2(dx)/(x\ sqrt(x^2-1))

int_(0)^(oo)(dx)/(x^(2)+2x cos theta+1)=2int_(0)^(1)(dx)/(x^(2)+2x cos theta+1)

"int_1^(2)((1)/(x)-(1)/(2x^(2)))dx

(i) int_0^1 (dx)/sqrt(1-x^2) (ii) int_0^1 (dx)/sqrt(1+x^2) (iii) a int_1^sqrt3 (dx)/(1+x^2) b int_0^1 (dx)/(1+x^2) (iv) int_0^(2//3) (dx)/(4+9x^2) (v) int_0^1 x/(x^2+1)dx (vi) int_2^3 x/(x^2+1) dx

int_(1)^(2)(dx)/((x-1)sqrt((x^(2)-2x)))= area of a circle then radiums of the circle is