Sketch the graph of `y=|x+3|` and evaluate the area under the curve `y=|x+3|` above x-axis and between `x=6` to `x=0.`

Explanation

`y = x+3`, when `x ge -3`

`y = -x-3`, when `x lt -3`

So, now we can draw the graph using these two equations.

Please refer to video to see the graph.

We have to find the area between `x = -6` to `x = 0`.

From the graph, we can see that required area is area of two right angle triangles.

`:.` Required Area `= 2(1/2*3*3) = 9` square units.