`K_(p)` for `CaCO_(3)(s) hArrCaO(s)+CO_(2)(g)` is `0.5` at `1000K ` 2 moles of `CaO(s) & CO_(2)(g)` each at `0.45 atm` introduce in a `16.4` lit. vessel and heated upto `1000 K`. The amount of `CaCO_(2)(s)` formed will be.

K_(p) for CaCO_(3)(s) hArrCaO(s)+CO_(2)(g) is 0.5 at 1000K 2 moles of CaO(s) & CO_(2)(g) each at 0.45 atm introduce in a 16.4 lit. vessel and heated upto 1000 K . The amount of CaCO_(3)(s) formed will be.

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

For the reaction : CaCO_(3) (s) hArr CaO (s) + CO_(2) (g)

Equilibrium constant K_(p) for the reaction CaCO_(3)(s) hArr CaO(s) + CO_2(g) is 0.82 atm at 727^@C . If 1 mole of CaCO_(3) is placed in a closed container of 20 L and heated to this temperature, what amount of CaCO_(3) would dissociate at equilibrium?

Equilibrium constant K_(p) for the reaction CaCO_(3)(s) hArr CaO(s) + CO_2(g) is 0.82 atm at 727^@C . If 1 mole of CaCO_(3) is placed in a closed container of 20 L and heated to this temperature, what amount of CaCO_(3) would dissociate at equilibrium?

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to