Given an acute triangle ABC such that `sin C=4/5,tan A=24/7 = and AB=50`.The area of triangle

24Given an acute triangle ABC such that sin C =-,tan A-7 and AB-50. Then-(A) centroid, orthocentre and incentre of AABC are collinear9.(B) sin B = 447sin B =-(D) area of AABC= 1200

Given a triangle Delta ABC such that sin^(2)A+sin^(2)C=1001.sin^(2)B .Then the value of (2(tan A+tan C)*tan^(2)B)/(tan A+tan B+tan C) is

Construct a triangle ABC in which AB=5 cm, BC=7 cm, and /_ABC=50^@ then construct a triangle similar to it, whose sides are 4//5 of the corresponding sides of first triangle.

In the figure, the area of triangle AEC and triangle ECB are 50 cm^2 and 75cm^2 . AB = 15 cm. What is the area of triangle ABC

In an acute angled triangle ABC, if tan(A+B-C)=1 and ,sec(B+C-A)=2, find the value of A,B and C.

In a triangle ABC if sin A sin B= ab//c^2 , then the triangle is

If Delta ABC, a = 18, b = 24, c = 30 then the area of the triangle is

If the area of the triangle ABC be triangle , show that, b^(2)sin 2C + c^(2) sin 2B= 4triangle .

In Delta ABC,AB=6cm,BC=7cm and AC=5cm .The area of Delta ABC is

In an acute angled triangle ABC, prove that tan^(2)a+tan^(2)B+tan^(2) C ge9 .