Question 34. From the curve y = 4x, y-axis and y = 3 The area of the enclosed area is:

Draw a rough sketch of the curve y^2=4x and find the area of the region enclosed by the curve and the line y=x.

Indicate the region bounded by the curves y=x^(2),y=x+2 and x -axis and obtain the area enclosed by them

The area between the curve y^(2) = 4x , y -axis and y = -1 and y = 3 is equal to:

The area between the curve y^(2) = 4x , y - axis and y = -1 and y = 3 is equal to

The area of the curve x + |y| = 1 and the y-axis is

The area of the curve x + |y| = 1 and the y-axis is

Mark the area bounded by the curve (y-1) (y-5) =4x and the y-axis and obtain the area by integration

The area enclosed between the curve y = 1 + x^(2) , the Y-axis and the straight line y = 5 is given by

The area of the region enclosed by the curves y=x , x =e y= (1)/(x) and the positive x axis is