The curve `y=ax^(3)+bx^(2)+cx` is inclined at `45^(@)` to x-axis at `(0,0)` but it touches x-axis at `(1,0)`, then

If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at (0, 0) but touches x-axis at (1, 0) , then

If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at (0, 0) but touches x-axis at (1, 0) , then

The curve y=ax^(3)+bx^(2)+cx is inclined at angle 45^(0) to x-axis at (0,0) but it touches X-axis at (1,0) then the value of a,b,c are given by

The curve y=ax^(3)+bx^(2)+cx is inclined by 45^(@) to x-axis at origin and it touches x-axis at (1,0). Then

The curve y=f(x)=ax^(3)+bx^(2)+cx is inclined at 45^(@) to positive direction of x -axis at (0,0), but it touches x -axis at (1,0) then value of ((f''(1)*f''(2))/(2f(2))) is

The curve y = ax ^(3) + bx ^(2) + cx + 5 touches the x-axis at P (-2, 0) and cuts the y-axis at a point Q where its gradient is 3, then 2a + 4b is equal to :

The curve y = ax^(3) +bx^(2) +cx +5 touches the x-axis at A(-2,0) and cuts the y-axis at a point B where its slope is 3. Then

The curve y=ax^(3)+bx^(2)+cx+5 touches the x -axis at P(-2,0) and cuts the y-axis at the point Q where its gradient is 3. Find the equation of the curve completely.

The curve y=ax^(3)+bx^(2)+cx+5 touches the x-axis at P(-2,0) and cuts the y-axis at a point Q where its gradient is 3. Find a,b,c.