" (2) Show that "|[a^(2)+x^(2),ab,ac],[ab,b^(2)+x^(2),bc],[ac,bc,c^(2)+x^(2)]|" is divisible by "x^(4)

Show that |(a^(2)+x^(2),ab,ac),(ab,b^(2)+x^(2),bc),(ac,bc,c^(2)+x^(2))| is divisible by x^(2) .

show that |[a^2+x^2,ab ,ac],[ab,b^2+x^2,bc],[ac,bc,c^2+x^2]| is divisible x^4

The determinant Delta = |(a^(2) + x^(2),ab,ac),(ab,b^(2) + x^(2),bc),(ac,bc,c^(2) + x^(2))| is divisible

The determinant Delta=|{:(a^(2)+x^(2),ab,ac),(ab,b^(2)+x^(2),bc),(ac,bc,c^(2)+x^(2)):}| is divisible by

The determinant Delta=|{:(a^(2)+x^(2),ab,ac),(ab,b^(2)+x^(2),bc),(ac,bc,c^(2)+x^(2)):}| is divisible by

|(a^(2)+x,ab,ac),(ab,b^(2)+x,bc),(ac,bc,c^(2)+x)|

|(-a^(2),ab,ac),(ab,-b^(2),bc),(ac,bc,-c^(2))|=

The determinant "det(A)"= |[ a^(2) +x,ab,ac], [ab, b^(2) +x,bc,] [ac,bc, c^(2) +x]| is divisible by a. x b. x^2 c. x^3 d. none of these

The determinant "det(A)"= |[ a^(2) +x,ab,ac], [ab, b^(2) +x,bc,] [ac,bc, c^(2) +x]| is divisible by a. x b. x^2 c. x^3 d. none of these (Correct options maybe more than one)

|(a^(2)+1,ab,ac),(ab,b^(2)+1,bc),(ac,bc,c^(2)+1)|=