Period of `(2sin2x-5cos2x)/(7cosx-8sinx)`

Period of (2sin2x-5cos2x)/(7cos x-8sin x) is KPi then K=

Period of ( 2 sin 2x -5 cos 2x )/( 7 cos x - 8 sin x) is

Period of |sin2x|+|cos8x| is

Solve sin2x-cos2x=sinx-cosx

sinx + cosx = (cos2x)/(1-sin2x)

int(2sin2x-cosx)/(6-cos^(2)x-4sinx)dx= a) log|sin^(2)x-4sinx+5|+7tan^(-1)(sinx-2)+C b) 2log|sin^(2)x-4sinx+5|+7tan^(-1)(sinx-2)+C c) 2log|sin^(2)x-4sinx+5|+C d) log|sin^(2)x+4sinx+5|+7tan^(-1)(sinx-2)+C

Solve: sinx-sin2x=cos2x-cosx

Period of cos((3x)/(5))-sin((2x)/(7)) is