" 3."quad " If "Aquad A=[[1,2],[4,2]]," if "facg|5(1|2A|=4|A|

|{:(1,-3,2),(4,-1,2),(3," "5,2):}|

A=[[2,3],[4,5],[2,1]] B=[[1,-2,3],[-4,2,5]] Find AB

If A=[(1,-2,3),(-4,2,5)],B=[(2,3),(4,5),(2,1)] then

If A^(-1)=(1)/(3)[[1, 4, -2], [-2, -5, 4], [1, -2, 1]] and |A|=3 , then adjA=

Show that A=A^(-1) if A[[-1,2,-2],[4,-3,4],[4,-4,5]] Hence find A^(2) .

The inverse of the matrix [[3, -2, -1], [-4, 1, -1], [2, 0, 1]] is a) [(1,2,3),(3,3,7),(-2,-4,-5)] b) [(1,-3,5),(7,4,6),(4,2,7)] c) [(1,2,3),(2,5,7),(-2,-4,-5)] d) [(1,-3,5),(7,4,6),(4,2,-7)]

Given A=[[1,2],[3,-1],[4,2]] , B=[[-1,4,-5],[2,1,0]] Show that ABneBA

I: If A=[(1,2),(3,4)] then A^(-1)=[(4,-2),(-3,1)] II: If A=[(3,4),(2,1)] then A^(-1)=1/5[(-1,4),(2,-3)]

If A=[[1,2,3]], B=[(-5,4,0),(0,2,-1),(1,-3,2)] then (A) AB=[(-2),(-1),(4)] (B) AB=[-2,-1,4] (C) AB=[4,-1,2] (D) AB=[(-5,4,0),(0,4,-2),(3,-9,6)]

If A=[[1,2,3]], B=[(-5,4,0),(0,2,-1),(1,-3,2)] then (A) AB=[(-2),(-1),(4)] (B) AB=[-2,-1,4] (C) AB=[4,-1,2] (D) AB=[(-5,4,0),(0,4,-2),(3,-9,6)]