[" Ar."],[[" (A) det "(A)," (B) "(1)/(det(A))," (C) "1," (D) "0]]

If A is an invertible matrix of order 2, then det (A^(-1)) is equal to (A) det (A) (B) 1/(det(A) (C) 1 (D) 0

If A is an invertible matrix of order 2, then det (A^(-1)) is equal to(a) det (A) (B) 1/(det(A) (C) 1 (D) 0

If A is an invertible matrix of order 2 then det (A^(-1)) is equal to (a) det (A) (b) (1)/(det(A))(c)1 (d) 0

If B is a non-singular matrix and A is a square matrix, then det (B^(-1) AB) is equal to (A) det (A^(-1)) (B) det (B^(-1)) (C) det (A) (D) det (B)

If B is a non-singular matrix and A is a square matrix, then det (B^(-1) AB) is equal to (A) det (A^(-1)) (B) det (B^(-1)) (C) det (A) (D) det (B)

If A and B are square matrices of order 2, then det(A+B)=0 is possible only when (a) det(A)=0 or det(B)=0 (b) det(A)+det(B)=0 (c) det(A)=0 and det(B)=0 (d) A+B=O

A square matrix A is invertible iff det (A) is equal to (A) -1 (B) 0 (C) 1 (D) none of these

Statement -1 : Determinant of a skew-symmetric matrix of order 3 is zero. Statement -2 : For any matrix A, Det (A) = "Det"(A^(T)) and "Det" (-A) = - "Det" (A) where Det (B) denotes the determinant of matrix B. Then,

Statement -1 : Determinant of a skew-symmetric matrix of order 3 is zero. Statement -2 : For any matrix A, Det (A) = "Det"(A^(T)) and "Det" (-A) = - "Det" (A) where Det (B) denotes the determinant of matrix B. Then,

A square matrix A is invertible if det(A) is equal to (A) -1 (B) 0 (C) 1 (D) none of these