From a lot of 10 bulbs, which includes 3 defectives, a sample of 2 bulbs is drawn at random. Find the probability distribution of the number of defective bulbs.

Explanation

let no of defective bulbs be `x`

`x= 0,1,2`

total ways`= .^10C_2`

ways in 2 defective`= .^3C_2`

ways of 1 defective`= .^3C_1.^7C_1`

ways of zero defectives`=.^7C_2`

`P(x=0) = (.^7C_2)/(.^10C_2) = ((7*6)/2)/((10*9)/2)`

`= 7/15`

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