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(200!)/((10!)^(20)19!)" is not an intege...

(200!)/((10!)^(20)19!)" is not an integer "

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Prove that :(200!)/((10!)^(20)19!) is an integer

.Let a_1, a_2, a_3... be in AP and g_1, g_2... be in GP If a_1, g_1=2 and a_(10) = g_(10)=3 , then (A) a_(19).g_7 is an integer (B) a_7g_(19) is an integer (C) a_(19)g_(10) is not an integer (D) none of these

. Let a_(1),a_(2),a_(3)... be in AP and g_(1),g_(2)... be in GP If a_(1),g_(1)=2 and a_(10)=g_(10)=3, then (A)a_(19*)g_(7) is an integer (B) a_(7)g_(19) is an integer (C) a_(19)g_(10) is not an integer (D) none of these

Let a and b be the 2 consecutive integers selected from the first 20 natural numbers. The probability that sqrt(a^(2) + b^(2) + a^(2)b^(2)) is an odd positive integer is a) (9)/(13) b) (10)/(19) c) (13)/(19) d)1

Solve 30x lt 200 , x is an integer

The sum of the series Sigma_(r = 0)^(10) ""^(20)C_(r) " is " 2^(19) + (""^(20)C_(10))/(2)

The sum of the series Sigma_(r = 0)^(10) ""^(20)C_(r) " is " 2^(19) + (""^(20)C_(10))/(2)

Following are some pairs of integers .Observe the following table and complete it . "Statement" " ""Obervation" (i) 17 +23 =40 " " "Result is an integer" (ii) -10+3=... " " ...................... (iii) (-75)+18= ...... " " ....... (iv) 19 +(-25)=-6 " " "Result is an integer" (v) 27+(-27)=..... " " ............ (vi) (-20)+0=...... " "............. (vii) (-35)+(-10)=........ " " ......... What do you observe ? Is the sum of two intergers always an integer? Did you find a pair of integers whose sum is not an integer ?

The mean weight of a group of 9 students is 19 kg . If a body of weight 29 kg is joined in the group , then find the mean weight of 10 students. The following are the steps involved in solving the above problem . Arrange them in sequential order . (A) The mean weight of 10 students = (200)/(10) kg (B) The total weight of 9 students = 9 xx 19 kg = 171 kg (C) The total weight of 10 students = (171 + 29) kg = 200 kg (D) therefore The mean weight = 20 kg

Solve 30x<200 when x is an integer.