[" (34) If "f(x)=(2-(256-7x)^(1/8))/((5x+32)^(1/5)-2),quad (x!=0)" ; "-x" ) "],[" Then for 'f to be continuous everywhere f(c) "],[" equal to: "]

If f(x) = (2 - (256 - 7x)^(1//8))/((5x + 32)^(1//5) - 2), x ne 0 , then for f to be continuous everywhere, f(0) is equal to :

If f(x)=(2-(256-7x)^(1//8))/((5x+32)^(1//5)-2) ( x ne 0) , then for f to be continuous on [-1,1] , f(0) is equal to

Thevalueof lim_(x rarr0)(2-(256-7x)^(1/8))/((5x+32)^(1/5)-2) is

The value of f(0) so that the function f(x)=(2-(256-7x)^(1/8))/((5x+32)^(1//5)-2),x!=0 is continuous everywhere, is given by

The value of f(0) so that the function f(x)=(2-(256-7x)^((1)/(8)))/((5x+32)^(1/5)-2),x!=0 is continuous everywhere,is given by -1( b) 1(c)26 (d) none of these

The value of f(0) so that the function f(x)=(2-(256-7x)^(1/8))/((5x+32)^(1//5)-2),x!=0 is continuous everywhere, is given by -1 (b) 1 (c) 26 (d) none of these

If f(x)=((256+ax)^((1)/(8))-2)/((32+bx)^((1)/(5))-2) is continuous at x=0 then the value of (a)/(b) is

If f (x) = (x^(2) - 10 x + 25)/( x^(2) - 7x + 10) and f is continuous at x =5, then f (5) is equal to