Find sum of first n squared natural numbers
i.e. `1^(2)+2^(2)+3^(2)+....+n^(2)`.

Property 6 The sum of first n odd natural numbers is n^(2)

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

The sum of the squares of first n natural numbers is -

If S_(n) denotes the sum of first 'n' natural numbers then s_(1)+S_(2)x+S_(3)x^(2)+.........+S_(n) x^(n-1)+......oo=(1-x)^(-n) then n is

If s_(n) denotes the sum of first 'n' natural numbers then S_(1)+S_(2)x+S_(3)x^(2)+.........+S_(n)x^(n-1)+......oo=(1-x)^(-n) then n is

If S_(n) denotes the sum of first 'n' natural numbers then S_(1)+S_(2)x+S_(3)x^(2)+........+S_(n)*x^(n-1)+.....oo= then n is

If S_(n) denotes the sum of first 'n' natural numbers then S_(1)+S_(2)x+S_(3)x^(2)+........+S_(n)*x^(n-1)+.. then n is

The sum of first n natural numbers is given 1/2 n^2 +1/2n . Find (i) The sum of first 5 natural numbers. (ii) The sum of first 11 natural numbers. (iii) The sum of natural numbers from 11 to 30.