Home
Class 12
PHYSICS
The work done to raise a mass m from the...

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is :

A

`(3)/(2)mgR`

B

`mgR`

C

`2 mgR`

D

`(1)/(2)mgR`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the work done to raise a mass \( m \) from the surface of the Earth to a height \( h \) equal to the radius of the Earth \( R \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Work Done**: The work done \( W \) in raising an object in a gravitational field is given by the change in gravitational potential energy (PE). The formula for gravitational potential energy is: \[ U = -\frac{G M m}{r} \] where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, \( m \) is the mass being raised, and \( r \) is the distance from the center of the Earth. 2. **Initial Potential Energy**: When the mass \( m \) is at the surface of the Earth, the distance \( r \) is equal to the radius of the Earth \( R \): \[ U_i = -\frac{G M m}{R} \] 3. **Final Potential Energy**: When the mass \( m \) is raised to a height \( h \) equal to the radius of the Earth, the new distance from the center of the Earth is \( R + h = R + R = 2R \): \[ U_f = -\frac{G M m}{2R} \] 4. **Calculating Work Done**: The work done \( W \) is the difference between the final and initial potential energies: \[ W = U_f - U_i \] Substituting the values we found: \[ W = \left(-\frac{G M m}{2R}\right) - \left(-\frac{G M m}{R}\right) \] Simplifying this expression: \[ W = -\frac{G M m}{2R} + \frac{G M m}{R} \] \[ W = \frac{G M m}{R} - \frac{G M m}{2R} \] \[ W = \frac{G M m}{2R} \] 5. **Relating to Gravitational Acceleration**: We know that the gravitational acceleration \( g \) at the surface of the Earth is given by: \[ g = \frac{G M}{R^2} \] Therefore, we can express \( G M \) as \( g R^2 \): \[ W = \frac{g R^2 m}{2R} = \frac{g m R}{2} \] 6. **Final Result**: Thus, the work done to raise the mass \( m \) to a height \( h \) equal to the radius of the Earth is: \[ W = \frac{1}{2} g m R \] ### Conclusion: The work done to raise a mass \( m \) from the surface of the Earth to a height equal to the radius of the Earth is \( \frac{1}{2} g m R \).

To solve the problem of calculating the work done to raise a mass \( m \) from the surface of the Earth to a height \( h \) equal to the radius of the Earth \( R \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Work Done**: The work done \( W \) in raising an object in a gravitational field is given by the change in gravitational potential energy (PE). The formula for gravitational potential energy is: \[ U = -\frac{G M m}{r} ...
Promotional Banner

Topper's Solved these Questions

  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise QUESTION|95 Videos
  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise MCQ|95 Videos
  • NEET

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise MCQ|95 Videos
  • MOTION IN TWO AND THREE DIMENSION

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise All Questions|47 Videos
  • NEET 2020

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise All Questions|45 Videos

Similar Questions

Explore conceptually related problems

The work done to take a particle of mass m from surface of the earth to a height equal to 2R is

If g is the acceleration due to gravity on earth's surface, the gain of the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

If g is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth, is

If 'g' is the potential energy of an object of mass 'm' raised from the surface of the earth to a height equal to the radius 'R' of the earth is

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass m raised from surface of the earth to a height equal to radius R of the earth is - [M = mass of earth]

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

An object of mass m is raised from the surface of the earth to a height equal to the radius of the earth, that is, taken from a distance R to 2R from the centre of the earth. What is the gain in its potential energy ?

If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body ofmass m from the earth's surface to a height R equal to the radius of the earth is

NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)-NEET-PHYSICS
  1. The correct Boolean operation represented by the circuit diagram drawn...

    Text Solution

    |

  2. When an object is shot from the bottom of a long smooth inclined plane...

    Text Solution

    |

  3. The work done to raise a mass m from the surface of the earth to a hei...

    Text Solution

    |

  4. The total energy of an electron in an atom in an orbit is -3.4eV. Its...

    Text Solution

    |

  5. In which of the following processes, heat is neither absorbed nor rele...

    Text Solution

    |

  6. A hallow metal sphere of radius R is uniformly charged. The electric f...

    Text Solution

    |

  7. Pick the wrong answer in the context with rainbow.

    Text Solution

    |

  8. A small hole of area of cross-section 2 mm^(2) present near the bottom...

    Text Solution

    |

  9. which of the following acts as a circuit protection device?

    Text Solution

    |

  10. Two point charges A and B, having charges +Q and -Q respectively, are ...

    Text Solution

    |

  11. Which colour of the light has the longest wavelength?

    Text Solution

    |

  12. The radius of cirlcue, the period of revolution, initial position and ...

    Text Solution

    |

  13. alpha-particle consists of

    Text Solution

    |

  14. A solid cylinder of mass 2 kg and radius 4 cm rotating about its axis ...

    Text Solution

    |

  15. In a double slit experiment, when light of wavelength 400 nm was used,...

    Text Solution

    |

  16. At a point A on the earth's surface of angle of dip, delta=+25^(@). A...

    Text Solution

    |

  17. A force F=20+10y acts on a particle in y-direction where F is in Newto...

    Text Solution

    |

  18. When a block of mass M is suspended by a long wire of length L, the l...

    Text Solution

    |

  19. A parallel plate capacitor 20 muF is being charged by a voltage source...

    Text Solution

    |

  20. A mass m is attached to a thin wire and whirled in a vertical circle. ...

    Text Solution

    |