Two drops of same radius are falling through air with steady velocity of `v" "cm//s`. If the two drops coalesce, what would be the terminal velocity ?

Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

Two drops of the same radius are falling through air with a steady velcoity of 5 cm s^(-1). If the two drops coalesce, the terminal velocity would be

Two drops of same radius are falling through air with steady speed v. If the two drops coalesce, what would be the terminal speed –

Two drops of same radius are falling through air with steady speed v. If the two drops coalesce, what would be the terminal speed –

Two water drops of the same radius are falling through air with a velocity 5cm/s. If the two drops coalesce to form one drop, the terminal velocity of the drop will be

Two equal drops of water are falling through air with a steady velocity of 10 cm/s. If the two drops recombine to a single drop, what will be the terminal velocity