For a particle showing motion under forces `F= - 5 ( x-2)` , the motion is

For a particle showing motion under forces F= - 5 ( x-2)^(2) , the motion is

For a particle showing motion under forces F= - 5 ( x-2)^(2) , the motion is

A particle moves under force F -5(x -2)^(3) .Motion of the particle is

A particle moves under force F =5(x -2)^(3) .Motion of the particle is

A particle of mass 0.50 kg executes a simple harmonic motion under a force F = – (50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s, find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.

A particle moves under the force F(x) = (x^(2) - 6x)N , where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?

A particle moves under the force F(x) = (x^(2) - 6x)N , where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?