A particle starts moving along the x-axis from `t=0`, its position varying with time as `x=2t^3-3t^2+1`.
a. At what time instants is its velocity zero?
b. What is the velocity when it passes through the origin?

A particle moves along the x-axis so that its position is given x = 2t^(3) –3t^(2) at a time t second. What is the time interval duringwhich particle will be on the negative half of the axis?

A particle moving according to the law s=6t-1/2t^3 . At what time its velocity vanishes ?

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

A particle moves along the x-axis in such a way that its x-co-ordinate varies with time as x = 2 – 5t + 6t^(2) . The initial velocity and acceleration of particle will respectively be-

A particle moves along the x-axis in such a way that its x-co-ordinate varies with time as x = 2 – 5t + 6t^(2) . The initial velocity and acceleration of particle will respectively be-

A particle is moving along x-axis. Its X-coordinate varies with time as, X=2t^2+4t-6 Here, X is in metres and t in seconds. Find average velocity between the time interval t=0 to t=2s.

A particle is moving along x-axis. Its X-coordinate varies with time as, X=2t^2+4t-6 Here, X is in meters and t in seconds. Find average velocity between the time interval t=0 to t=2s.

A particle is moving along x-axis such that its velocity varies with time according to v=(3m//s^(2))t-(2m//s^(3))t^(2) . Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.