[3x+y+2z=3],[-2x+3y+z=3],[-x+2y+z=4]

2x = 3y = 4z, x: y: z

3x+4y+7z=4, 2x+y+ 3z= 3, x + 2y +3z =8.

Prove that |[x, y, z],[x^2, y^2, z^2], [x^3, y^3, z^3]|=xyz(x-y)(y-z)(z-x)

2x+3y+z=17,x-y+z=3,3x+2y-2z=4

Show that : |[x, y, z ],[x^2,y^2,z^2],[x^3,y^3,z^3]|=x y z(x-y)(y-z)(z-x)dot

If ({:(3x -y, x + 3y),(2x - z, 2y +z):}) = ({:(7,9),(5,5):}), then x + y + z equals

What should be added to x y+y z+z x to get x y-y z-z x ? -2x y-2y z-2z x (b) -3x y-y z-z x -3x y-3y z-3z x (d) 2x y+2y z+2z x

Using matrices, solve the following system of equations for x,y and z: 2x+3y + 3z=5, x-2y + z = -4, 3x-y - 2z=3