" (n) "int(x^(2)+1)/(x^(2)-1)dx" an "47

int(2x^(n-1))/(x^(n)+3)dx

(i) int((x^(2) - 1)/(x^(2) + 1))dx , (ii) int ((x^(6)- 1)/(x^(2) + 1))dx (iii) int ((x^(4))/(1+x^(2)))dx , (iv) int((x^(2))/(1+x^(2)))dx

int(1)/((x^(2)+k)^(n))dx

int (x + (1)/(x)) ^(n +5) ((x ^(2) -1)/( x ^(2))) dx is equal to:

int (2x^(n-1))/(x^n+3) dx

If I_(1)=int_(0)^(oo) (dx)/(1+x^(4))dx and I_(2)=underset(0)overset(oo)int x^(2)(dx)/(1+x^(4))"then"n (I_(1))/(I_(2))=

Evaluate : (i) inte^(x)((1)/(x)-(1)/(x^(2)))dx (ii) inte^(x)((1)/(x^(2))-(2)/(x^(3)))dx (iii) inte^(x){sin^(-1)x+(1)/(sqrt(1-x^(2)))}dx (iv) inte^(x)(tanx+logsecx)dx

int(x+(1)/(x))^(n+5).((x^(2)-1)/(x^(2)))dx is equal to

int(x+(1)/(x))^(n+5).((x^(2)-1)/(x^(2)))dx is equal to