K_(4)[Ni(CN)_(4)]

All alkali metals dissolve in anhydrous liquid ammonia to give blue colour solution. It is the ammoniated electron which is reponsible for the blue colour of the solution, and the electrical conductivity is due to the ammoniated cation, [M(NH_(3))_(x)]^(+) as well as the ammoniated electron, [e(NH_(3))_(y)]^(-) , value of x and y depend on the extent of solvation by NH_(3) . Dilute solutions are paramagnetic due to free ammoniated electrons. Q. Ammoniated solutions of alkali metals are reducing agents due to the presence of free ammoniated or solvated electrons that can reduce: (I) O_(2) "to" O_(2)^(2-) (II) K_(2)[Ni(CN)_(4)] " to "K_(4)[Ni(CN)_(4)] (III) Aromatic ring (IV) Non-terminal alkyne Choose the correct code:

Calculate the oxidation number of Ni in K_(2)[Ni(CN)_(4)] .

Calculate the oxidation number of Ni in K_(2)[Ni(CN)_(4)] .

The IUPAC name of the K_(2)[Ni(CN)_(4)] is :

The IUPAC name of K_(2)[Ni(CN)_(4)] is :