1L of `CO_(2)` is passed over hot coke . then volume after complete reaction is ? when the vol of reaction mix becomes 1.4L

Options

A. `0.6 L CO_(2)`
B. `0.8 L CO_(2)`
C. `0.6 L CO_(2)and 0.8 L CO`
D. `2 L`

Answer

To solve the problem of how much volume of CO2 is left after passing 1L of CO2 over hot coke, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reaction**: The reaction between carbon dioxide (CO2) and coke (carbon) can be represented by the balanced equation:
\[ CO_2 + C \rightarrow 2CO \]
This means that 1 mole of CO2 reacts with 1 mole of carbon to produce 2 moles of carbon monoxide (CO).

2. **Initial Volume of CO2**: We start with 1 liter of CO2.

3. **Let x be the volume of CO2 that reacts**: Since 1 liter of CO2 is passed over hot coke, we can denote the volume of CO2 that reacts as \( x \) liters. Therefore, the volume of unreacted CO2 will be:
\[ \text{Unreacted CO2} = 1 - x \text{ liters} \]

4. **Calculate the Volume of CO Produced**: According to the reaction, for every volume \( x \) of CO2 that reacts, \( 2x \) liters of CO are produced.

5. **Total Volume of the Reaction Mixture**: The total volume of the gas mixture after the reaction is given as 1.4 liters. This total volume can be expressed as the sum of the unreacted CO2 and the produced CO:
\[ \text{Total Volume} = \text{Unreacted CO2} + \text{CO produced} \]
Substituting the expressions we have:
\[ 1.4 = (1 - x) + 2x \]

6. **Solve for x**:
\[ 1.4 = 1 - x + 2x \]
\[ 1.4 = 1 + x \]
\[ x = 1.4 - 1 = 0.4 \text{ liters} \]

7. **Calculate the Volume of CO Produced**:
\[ \text{Volume of CO} = 2x = 2 \times 0.4 = 0.8 \text{ liters} \]

8. **Calculate the Volume of Unreacted CO2**:
\[ \text{Unreacted CO2} = 1 - x = 1 - 0.4 = 0.6 \text{ liters} \]

### Final Result:
- The volume of CO2 that reacted is 0.4 liters.
- The volume of CO produced is 0.8 liters.
- The volume of unreacted CO2 is 0.6 liters.