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(4(2)/(3)times(9)/(14)+5(1)/(6)times2(2)...

`(4(2)/(3)times(9)/(14)+5(1)/(6)times2(2)/(5))` of `417(7)/(8)`=

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(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(2)/(5)times((-3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

Using appropriate properties find. (i) -(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(1)/(6) (ii) (2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(9)/(2)-:(7)/(5)times(4)/(6)-:(2)/(3)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

Simplify -(2)/(3)times5(1)/(2)times2times7(5)/(6)times(9)/(11)

( (5)/(6)-:(6)/(7)times(6)/(7)-(8)/(9)-:1(3)/(5)+(3)/(4)times3(1)/(3)

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)

Simplify : [ ((- 3 )/( 2) xx (4)/(5) ) + ((9)/(5) xx (-10)/( 3)) - ((1)/(2)xx (3)/(4)) ] div [ ((21)/( 9) xx (3)/(7)) +((7)/(8) xx (16)/(14)) ]