[" Using prof,"," P/T "],[,2n+7<(n+5)^(2)]

The n^(th) term of a sequence is given by T_n = 2n + 7. Show that it is an A.P. Also, find its 7^(th) term.

If t_(n)" is the " n^(th) term of an A.P., then t_(2n) - t_(n) is …..

By using the principle of mathematical induction , prove the follwing : P(n) : (2n + 7) lt (n+3)^2 , n in N

In the given figure (circle), P T=5,P D=7a n dP A=2, then the value of P B-P C=?

In the given figure (circle), P T=5,P D=7a n dP A=2, then the value of P B-P C=? Fig

If the fourth term in the expansion of (x/p + 1/x)^n , n epsilon N is 5/2 and the normal to the parabola y^2 = 4ax , at (at^2, 2at) meets the parabola again at (aT^2, 2aT) , then (A) T^2 = p+n (B) T^2 gt p+n (C) T^2 ge p+n (D) T^2 le p + n

Find the missing term. N 5 V, K 7 T, ?, E 14 P, B 19 N

Using mathematical induction prove that (2n+7) lt (n+3)^2 for all n in N

If t_(n)" is the " n^(th) term of an A.P. then the value of t_(n+1) -t_(n-1) is ……

If it,be the n^(th) term of an A.P and if t_(7)=9 then the value of the c.d.that would make t_(1)t_(2)t_(7), least is