show that there is no value of n for which ` ( 2^(n) xx 5 ^(n))` ends in 5.

For what value of n,2^(n)xx5^(n) ends in 5

For what value of n ,\ 2^nxx5^n ends in 5.

For any 'n', 6^(n) - 5^(n) ends with

Find the value of n, if 12 xx ^((n-1))P_3= 5 xx ^((n+1))P_3

If m, n are natural numbers, for what values of m, does 2^(n)times5^(m) ends in 5?

If n ends in 5, then n^3 ends in 25.

Find the value of n in each of the following: (i) 2^(n-7)xx5^(n-4)=1250 (ii) 5^(n-2)xx3^(2n-3)=135

Find the value of n such that "(i) "^(n)P_(5) =42 xx ""^(n)P_(3), n gt 4 " (ii) "(""^(n)P_(4))/(" "^(n-1)P_(4))=(5)/(3), n gt 4.

Find the value of n such that "(i) "^(n)P_(5) =42 xx ""^(n)P_(3), n gt 4 " (ii) "(""^(n)P_(4))/(" "^(n-1)P_(4))=(5)/(3), n gt 4.