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The Cartesian product A xxA has 9 eleme...

The Cartesian product `A xxA ` has 9 elements among which are found `(-1, 0) " and " (0, 1)`. Find the set `A` and the remaining elements of `A xxA`.

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To solve the problem, we need to find the set \( A \) and the remaining elements of the Cartesian product \( A \times A \) given that it has 9 elements, including the pairs \((-1, 0)\) and \((0, 1)\). ### Step 1: Determine the elements of set \( A \) Given the two pairs \((-1, 0)\) and \((0, 1)\), we can deduce the elements of set \( A \). From the pair \((-1, 0)\): - The first element is \(-1\) ...
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Knowledge Check

  • The cartesian products A xxA has 9 elements among which are found (-1,0) and (0,1). Then, the remaining elements of A xx A are

    A
    (0,0),(0,1),(0,-1)(-1,1),(-1,0),(1,0),(1,-1)
    B
    (-1,1),(-1,0),(0,0),(0,-1),(0,1),(1,0),(1,-1)
    C
    (0,-1),(1,0),(1,-1)
    D
    None of the above

  • Let A be a non-empty set such that A xx A has 9 elements among which are found (-1, 0) and (0, 1). Then,

    A
    A = {-1, 0}
    B
    A = {0, 1}
    C
    A = {-1, 0, 1}
    D
    A = {-1, 1}

  • If AxxA has 9 elements two of which are (-1,0) and (0,1) then the set A is

    A
    `{-1,0}`
    B
    `{-1,1}`
    C
    `{-1,0,1}`
    D
    `{0,1}`

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