When `45gm` solution is dissolved in `600gm`water freezing point lower by `2.2K`,calcuate molar mass of solute `(K_(f)=1.86 "kg mol"^(-1))`

If 10.0 g of a non-electrolyte dissolved in 100 g of water lowers the freezing point of water by 1.86^(@)C , the molar mass of the non-electrolyte is ( K_(f)=1.86 Km^(-1) )

34.2 gm Sucrose (Molecular wt 342) is dissolved in 1000 gm of water. Find the freezing-point of the solution kf = 1.86 K Kg mol^-1

A solution containing 25. 6 gm of sulphur dissolved in 1000 gm of napthalene gave a freezing point lowering of 0.680, then molecular formula of sulphare is (K_(f) for naphthalene=6.8K kg mol^(-1) )

31 g of ethylene glycol (C_2H_6O_2) is dissolved in 600g of water. The freezing point depression of the solution is (K_f for water is 1.86 K Kg mol^-1)