By how which would the stopping potential for a given photosensitive surface go up if the frequency of the incident radiations were to be increased from `4xx10^(15)Hz` to `8xx10^(15)Hz`? Given, `h=6.6xx10^(-34)Js`, `e=1.6xx10^(-19)C and c=3xx10^8ms^-1`.

By how which would the stopping potential for a given photosensitive surface go up if the frequency of the incident radiations were to be increased from 6xx10^(15)Hz to 16xx10^(15)Hz ? Given, h=6.6xx10^(-34)Js , e=1.6xx10^(-19)C and c=3xx10^8ms^-1 .

By how much would the stopping potential for given photosensitive surface go up if the frequency of the incident radiations were to be increased from 4xx10^(15) Hz to 8xx10^(15)Hz ? Given h = 6.4xx10^(-34) J.s, e = 1.6xx10^(-19)C and c = 3xx10^(8) m.s^(-1) .

Calculate the change in stopping potential for a photosensitive surface when frequency of light on the surface changes from 2xx10^(15) Hz to 6xx10^(15)Hz

If the frequency of the incident radiation is increased from 4xx10^(15)Hz to 8xx10^(15)Hz . by how much will the stopping potential for a given photo-sensitive surface go up ?

Calculate the momentum of a photon of frequency 5 xx 10^(13) Hz .Given, h = 6.6 xx 10^(-34)J.s and c = 3 xx 10^(8) m.s^(-1)

Calculate momentum of photon. Frequency associated with the photon is 5 xx 10^(13) Hz. Given h6.6 xx 10^(-34) Js and c=3 xx 10^(8) ms^(-1)

Calculate momentum of photon. Frequency associated with the photon is 1.5 xx 10^(13) Hz. Given h6.6 xx 10^(-34) Js and c=3 xx 10^(8) ms^(-1)