In right angled `DeltaBAC,/_BAC=90^(@)` ,segments `AD, BE` and `CF` are medians.Prove that `2(AD^(2)+BE^(2)+CF^(2))=3BC^(2)`

In triangleABC , AD, BE, CF are the medians. Prove that, 4(AD^(2)+BE^(2)+CF^(2))= 3(AB^(2)+BC^(2)+AC^(2)) .

In the right-angled ABC, /_A =1 right angle. BE and CF are two medians of Delta ABC . Prove that 4 ( BE^(2) + CF^(2)) =5 BC^(2)

If AD , BE and CF are medians of DeltaABC , then bar(AD) + bar(BE) + bar(CF) =

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)

If AD, BE and CF are the medians of a ABC ,then (AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2)) is equal to

In figure - 6 in an equilateral triangle ABC, AD_|_BC, BE_|_AC and CF_|_AB . Prove that 4(AD^(2)+BE^(2)+CF^(2))=9AB^(2)

In figure - 6 in an equilateral triangle ABC, AD_|_BC, BE_|_AC and CF_|_AB . Prove that 4(AD^(2)+BE^(2)+CF^(2))=9AB^(2)

In Delta ABC,/_A = right angle. If CD is a median, then prove that BC^(2) = CD^(2)+ 3AD^(2) .

In an acute angled triangle ABC, AD is the median in it. Prove that : AD^(2) = (AB^(2))/2 + (AC^(2))/2 - (BC^(2))/4