In Ampere's law `(oint (vec B).(vec dl))=(mu_0)I`, the current outside the curve is not included on the right hand side. Does it mean that the magnetic field B calculated by using Ampere's law , gives the contribution of only the currents crossing the area bounded by the curve?

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. In the above question, find the magnetic field induction at a point distance r from the axis when rgta. Assume relative permeability of the medium surrounding the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. In the above question, find the magnetic field induction at a point distance r from the axis when rgta. Assume relative permeability of the medium surrounding the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. If the current density in a linear conductor of radius a varies with r according to relation J=kr^2 , where k is a constant and r is the distance of a point from the axis of conductor, find the magnetic field induction at a point distance r from the axis when rlta. Assume relative permeability of the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. If the current density in a linear conductor of radius a varies with r according to relation J=kr^2 , where k is a constant and r is the distance of a point from the axis of conductor, find the magnetic field induction at a point distance r from the axis when rlta. Assume relative permeability of the conductor to be unity.

Ampere's law provides us an easy way to calculate the magnetic field due to a symmetrical distribution of current. Its mathemfield expression is ointvecB.dl=mu_0I_("in") . The quantity on the left hand side is known as line as integral of magnetic field over a closed Ampere's loop. Only the current inside the Amperian loop contributes in