`NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g)` If equilibrium pressure is 3 atm for the above reaction, then `K_(p)` for the reaction is

NH_(4)COONH_(4)(s) hArr 2NH_(3)(g)+CO_(2)(g) . If equilibrium pressure is 3 atm for the above reaction, K_(p) will be

NH_(2)COONH_(2)(s) harr 2NH_(3)(g) + CO_(2)(g) If equilibrium pressure is 3 atm for the above reaction, K_(p) will be

NH_4COONH_2 (s) hArr 2NH_3(g)+CO_(2)(g) If equilibrium pressure is 6 atm for the above reaction, K_p will be :

NH_4COONH_2 (s) hArr 2NH_3(g)+CO_(2)(g) If equilibrium pressure is 4 atm for the above reaction, K_p will be :(volume and temperature are constant)

NH_4COONH_2 (s) hArr 2NH_3(g)+CO_(2)(g) If equilibrium pressure is 2 atm for the above reaction, K_p will be :(volume and temperature are constant)