In Figure, `A P\ _|_l\ a n d\ P R > P Q` . Show that `A R > A Q` Given: `A P_|_l\ a n d\ P R > P Q` To Prove: `A R > A Q` Construction: Mark a point `S` on `P R` such that `P S=P Qdot` Join `A S`

In figure, P Q=P R . Show that P S > P Q .

In Figure, P S=P R ,\ \ /_T P S=\ /_Q P Rdot Prove that P T=P Q

In Figure, P S=Q R\ a n d\ /_S P Q=/_R Q Pdot Prove that P Q S\ ~=\ Q P R ,\ P R=Q S\ a n d\ /_Q P R=\ /_P Q S

In Figure, If P Q=P T\ a n d\ /_T P S=/_Q P R , prove that \ P R S is isosceles

In Figure, /_P Q R=\ /_P R Q , then prove that /_P Q S=\ /_P R Tdot

In Fig 7.51, P R\ >\ P Q and PS bisects /_Q P R . Prove that /_P S R\ >/_P S Q .

In Fig 7.51, P R\ >\ P Q and PS bisects /_Q P R . Prove that /_P S R\ >/_P S Q .

In Figure, T is a point on side Q R of P Q R and S is a point such that R T=S Tdot Prove That : P Q+P R > Q S

In Figure, P Q R is a triangle and S is any point in its interior, show that SQ+SR < PQ+PR. Given : S is any point in the interior of P Q R To Prove : S Q+S R < P Q+P R Construction: Produce Q S to meet P R in T

In Figure, P Q R is a triangle and S is any point in its interior, show that S Q+S R