If sum of 3 terms of a `G.P.` is `S` product is P ,and sum of reciprocal of its terms is R , then `P^2` `R^3` equals to-

In a G.P the sum of first n terms is S,the product is P and the sum of the reciprocals of the terms is R.Show that P^2=(S/R)^n .

if S is the sum , P the product and R the sum of reciprocals of n terms in G.P. prove that P^2 R^n=S^n

if S is the sum , P the product and R the sum of reciprocals of n terms in G.P. prove that P^2 R^n=S^n

The sum of 2n terms of a series in G.P. is 2R and the sum of the reciprocals of those terms is R , find the continued product of the terms.

If S be the sum, p the product and R the sum of the reciprocals of n terms of a G.P., then (S/R)^n is equal to

If S be the sum,p the product and R the sum of the reciprocals of n terms of a G.P.,then ((S)/(R))^(n) is equal to

If S is the sum, P the product and R the sum of reciprocals of n terms of a G.P., then prove that P^2 = (S/R)^n .

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. then P^2R^3: S^3 is equal to (a) 1:1 (b) (common ratio)^n :1 (c) (First term)^2(common ratio)^2 (d) None of these

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. then P^2R^3: S^3 is equal to (a)1:1 (b) (common ratio)^n :1 (c)(First term)^2(common ratio)^2 (d) None of these