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A die has two faces each with number ' 1...

A die has two faces each with number ' 1three faces each with number '2' and one face with number '3'.If die is rolled once, determine
(i) P(2) (ii) P(1 or 3) (iii) P(not 3)

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AI Generated Solution

To solve the problem, we will calculate the probabilities step by step. ### Given: - A die has: - 2 faces with the number '1' - 3 faces with the number '2' - 1 face with the number '3' ...
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A die has two faces each with number 1, three faces each with number 2 and one face with number 3. If the die rolled once,determine (i) P(1) (ii) P(1 or 3) (iii) P( not3)

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Knowledge Check

  • There are two die A and B both having six faces. Die A has three faces marked with 1 , two faces marked with 2 , and one face marked with 3 . Die B has one face marked with 1 , two faces marked with 2 , and three faces marked with 3 . Both dices are thrown randomly once. If E be the event of getting sum of the numbers appearing on top faces equal to x and let P(E) be the probability of event E , then P(E) is maximum when x equal to

    A
    5
    B
    3
    C
    4
    D
    6

  • There are two die A and B both having six faces. Die A has three faces marked with 1, two faces marked with 2, and one face marked with 3. Die B has one face marked with 1, two faces marked with 2, and three faces marked with 3. Both dices are thrown randomly once. If E be the event of getting sum of the numbers appearing on top faces equal to x and let P(E) be the probability of event E, then P(E) is minimum when x equals to

    A
    3
    B
    4
    C
    5
    D
    6

  • There are two die A and B both having six faces. Die A has three faces marked with 1, two faces marked with 2, and one face marked with 1, two faces marked with 2, and one face marked with 3. Die B has one face marked with 1, two faces marked with 2, and three faces marked with 3. Both dices are thrown randomly once. If E be the event of getting sum of the numbers appearing on top faces equal to x and let P(E) be the probability of event E, then When x = 4, then P(E) is equal to

    A
    `5//9`
    B
    `6//7`
    C
    `7//18`
    D
    `8//19`

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