Evaluate: int(cos2x-cos2alpha)/(cosx-cos...

Evaluate: `int(cos2x-cos2alpha)/(cosx-cosalpha)\ dxdot`

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To evaluate the integral \[ I = \int \frac{\cos(2x) - \cos(2\alpha)}{\cos(x) - \cos(\alpha)} \, dx \] we can follow these steps: ...

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Evaluate: int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

Knowledge Check

int(cos(x+alpha))/cosx dx=

A

`(cosalpha)x-sinalphalogabs(cosx)+c`

B

`(cosalpha)x-sinalphalogabs(secx)+c`

C

`(cosalpha)x+sinalphalogabs(secx)+c`

D

`(cosalpha)+sinalphalogabs(cosx)+c`

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