The volumes of two bodies are measured to be
`V_1 = (10.2+-0.02) cm^3 and V_2 = (6.4 +- 0.01)cm^3`. Calculate sum and difference in volumes with error limits.

Answer

A, B, C, D

Explanation

`V_1 = (10.2+-0.02)cm^3`
and `V_2 =(6.4 +- 0.01)cm^3`
`DeltaV= +-(DeltaV_1 + DeltaV_2)`
` =+- (0.02 + 0.01) cm^3 = +-0.03 cm^3`
`V_1 + V_2 = (10.2 + 6.4)cm^3= 16.6cm^3`
and ` V_1 - V_2 = (10.2 -6.4)cm^3 = 3.8 cm^3`
Hence, sum of volumes `= (16.6 +- 0.03)cm^3`
and difference of volumes = `(3.8 +-0.03) cm^3` .