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Find the percentage error in specific re...

Find the percentage error in specific resistance given by `rho = (pir^2R)/(l)` where r is the radius having value `(0.2+-0.02)`cm, R is the resistance of `(60+-2) ohm` and l is the length of `(150+-0.1)`cm.

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The correct Answer is:
B, C, D
`(Delta rho)/(p) xx 100=[2(Deltar)/(r)+(DeltaR)/(R)+(DeltaI)/(I)]xx100 `
` =[(2xx0.002)/(0.2)+(2)/(60)+(0.1/150)]xx100 `
`23.4%`
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