A meter bridge is set- up as shown in figure, to determine an unknown resistance `X` using a standard ` 10 Omega` resistor. The galvanometer shows null point when tapping - key is at `52 cm` mark. The end -corrections are `1 m` and `2 cm` respectively for the ends `A` and `B`. The determined values of `X` is . (a) `10.2 Omeaga` (b) `10.6 Omega` (c) `10.8 Omega` (d) `11.1 Omega`.
Text Solution
Verified by Experts
The correct Answer is:
B
Using the concept of balanced, Wheatstone bridge, we have, `P/Q = R/S` `:. X/((52 +1))=(10)/((48 + 2))` `:. X=(10 xx 53)/(50) =10.6 Omega` `:.` Correct option is (b).
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