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The end correction ( e) is (l(1) = lengt...

The end correction ( e) is `(l_(1)` = length of air column at first resonance and `l_(2)` is length of air column at second resonance).

A

`e = (l_2-3l_1)/2`

B

`e = (l_1-3l_2)/2`

C

`e = (l_2-2l_1)/2`

D

`e = (l_1-2l_2)/2`

Text Solution

Verified by Experts

The correct Answer is:
A
.
`l_1 + e=lamda/4`
`l_2 + e= (3 lamda)/4`
Solving these two equations, we get
`e = (l_2-3l_1)/2`.
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