In an experiment to determine the specific heat of aluminium, piece of aluminimum weighing `500 g` is heated to `100 .^(@) C`. It is then quickly transferred into a copper calorimeter of mass `500 g` containing `300g` of water at `30 .^(@) C`. The final temperature of the mixture is found to be `146.8 .^(@) c` . If specific heat of copper is `0.093 cal g^-1 .^(@) C^-1`, then the specific heat aluminium is.

Options

A. `0.11 cal g^-1 .^(@) C^-1`.
B. `0.22 cal g^-1 .^(@) C^-1`.
C. `0.33 cal g^-1 .^(@) C^-1`.
D. `0.44 cal g^-1 .^(@) C^-1`.

Answer

B

Explanation

Heat lost by aluminium = `500 xx s xx (100- 46.8)` cal
`:.` Heat lost = `26600 s`
Heat gained by e = water and calorimeter.
= `300 xx 1 xx (46.8-30)`
`+ 500 xx 0.093 xx (46.8 -30)`
`:.` Heat gained = `5040 +781.2 = 5821.2`
`:.` Now, heat lost = Heat gained
`:. 26600 s = 5821.2`
`:. s = 0.22 cal g^-1 (.^(@) C)^-1`.