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Force acting on a perticle is 5 N. If un...

Force acting on a perticle is 5 N. If units of length and time are double and unit of mass is holved then find the numerical value of force in the new system of unit .

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`"Force" = 5 N = (5kg-m)/(s^(2)) `
If unit of length and time are doubled and unit of mass is halved , then of force of new system of units will be
` 5[[(1)/(2) xx2)/((2)^(2)]] = (5)/(4)`
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