Home
Class 11
PHYSICS
The relation between the"energy" E and t...

The relation between the`"energy" E `and the freqency ` v `of a photon is repressed by the equation` E = hv `, where h is plank's Writen down ` s_(t) = u + (a)/(2) (2t-1)` , where u is initial of h and its dimensions.

Text Solution

Verified by Experts

The correct Answer is:
A, B
` h = ( E)/(gamma) = (j)/(s^(-1)) = J-s`
`[k] = [ML^(3)T^(-2)][T]`
` = [ML^(2)T^(-1)]`
Promotional Banner

Topper's Solved these Questions

  • UNIT AND DIMENSIONS

    DC PANDEY|Exercise Assertion And Reason|2 Videos

  • UNIT AND DIMENSIONS

    DC PANDEY|Exercise More Than One Correct|5 Videos

  • THERMOMETRY,THERMAL EXPANSION & KINETIC THEORY OF GASES

    DC PANDEY|Exercise Level 2 Subjective|9 Videos

  • UNITS, DIMENSIONS & ERROR ANALYSIS

    DC PANDEY|Exercise Medical entrances gallery|32 Videos

Similar Questions

Explore conceptually related problems

Find the dimensions of Planck's constant h from the equatioin E=hv where E is the energy and v is the frequency.

With the usual notations , check if the following equation S_(t) = u + (1)/(2) a ( 2t -1) is dimensionally correct or not.

Whether a given relation / formula is correct or not can be checked on the basis of the principle of homogeneity of dimensions. According to this principle, only that formula is correct, in which the dimensions of the various terms on one side of the relation are equal to the respective dimensions of these terms on the other side of the relation. With the help of the compreshension given above, choose the most appropriate alternative for each of the following questions : The distance travelledl by a body in nth second is given by S_(nth) = u + (a)/(2) (2n-1) where u is initial velocity and a is acceleration. The dimensions of S_(nth) are

If the enrgy of a frequency v is gives by E = hv where h is plank's constant and the momentum of photon is p = h//lambda where lambda is the wavelength of photon , then the velocity of light is equal to

We may state that the energy E of a photon of frequency v is E =hv, where h is a plank's constant. The momentum p of a photon is p=h//lambda where lambda is the wavelength of the photon. From the above statement one may conclude that the wave velocity of light is equal to

Check the correctness of the relation s_(t) = u+ (a)/(2) (2t-1) where u is initial velocity a is acceleration and s_(t) is the diplacement of the body in t^(th) second .

Write the dimensions of a xx b in the relation E = ( b - x^(2))/( at) , where E is the energy , x is the displacement , and t is the time.

Prove the relation, s_t=u + at - 1/2 a.

Photon is quantum of radiation with energy E =hv where v is frequency and h is Planck's constant. The dimensions of h are the same as that of