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Find magnitude and directon of a vector...

Find magnitude and directon of a vector, `A = (6hati - 8 hat j)`.

Text Solution

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`|A| or A = sqrt((6)^2+(-8)^2)`
`= 10 units`. Direction of A vector A can be shown as
`tan alpha = (8)/(6) = (4)/(3)`
`:. alpha = tan^(-1)((4)/(3)) = 53^@`
Therefore, A is making an angle of `53^@` from positive x- axis towards negative y-axis.
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