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Find the angle between two vectors A= 2 ...

Find the angle between two vectors `A= 2 hat j + hat j - hat k` and `B=hat j - hat k` and `B = hati - hatk` .

Text Solution

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`A=|A| = sqrt((2)^2 +(1)^2 (-1)^2) = sqrt6`
`B= |B| = sqrt((1)^2 +(-1)^2) = sqrt2`
`A.B = (2 hat i+ hat j - hat k)`
`=(2)(1)+(1)(0) + (-1)(-1) =3`
Now,` cos theta = (A.B)/(AB) = (3)/(sqrt6. sqrt2)`
`=(3)/(sqrt12) = (sqrt3)/(2)`
`:. theta = 30^@1` .
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