Home
Class 11
PHYSICS
Find component of vector A +B along (i) ...

Find component of vector A +B along (i) x-axis, (ii) C. Given `A = hati - 2hatj, B=2hatj+3hatk` and `C = hati +hatj`.

Text Solution

Verified by Experts

`A+B=(hati - 2hatj)+(2hati+3hatk) = 3hatj- 2hatj+3hatk`
(i) Component of A+B along x-axis is 3.
(ii) Component of A+B = R (say) along C is
`R cos theta =(R.C)/(C ) = R cos theta=(R.C)/(C)=((3hati-2hatj+3hatk).(hati+hatj))/(sqrt((1)^(2)+(1)^(2)))=(3-2)/(sqrt2)=(3)/(sqrt(14))`
`theta=cos^(-1)((3)/(sqrt(14)))`
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    DC PANDEY|Exercise Exercise 5.1|5 Videos
  • VECTORS

    DC PANDEY|Exercise Exercise 5.2|4 Videos
  • UNITS, DIMENSIONS & ERROR ANALYSIS

    DC PANDEY|Exercise Medical entrances gallery|32 Videos
  • WAVE MOTION

    DC PANDEY|Exercise Integer Type Question|11 Videos

Similar Questions

Explore conceptually related problems

Find the components of a vector A = 2hati + 3hatj along the directions of hati + hatj and hati - hatj.

if A = 2hati - 3hatj+7hatk, B = hati + 2hatj and C=hatj - hatk . Find A(BxxC)

Find magnitude of A-2 B 3 C, where, A = 2hati+3hatj, B = hati + hatj and c =hatk.

Find the components of a vector vecA=2hati+3hatj along the directions of hati+hatj and hati-hatj

Find the components of vec(a) = 2hati +3hatj along the direction of vectors hati +hatj and hati - hatj .

Find the area of the triangle formed by the tips of the vectors vec(a) = hati - hatj - 3hatk, vec(b) = 4hati - 3hatj +hatk and vec(c) = 3 hati - hatj +2 hatk .

The position vectors of the points A,B and C are (2hati + hatj - hatk), (3hati - 2hatj + hatk) and (hati + 4hatj - 3hatk) respectively. Show that the points A,B and C are collinear.

Find a unit vector perpendicular to plane ABC when position vectors of A,B,C are 3 hati - hatj + 2hatk, hati - hatj- 3hatk and 4 hati - 3 hatj + hatk respectively.

The vector component of vector vecA =3hati +4hatj +5hatk along vector vecB =hati +hatj +hatk is :

If the position vector of the vertices A,B and C of a DeltaABC be (hati + 2hatj + 3hatk), (2hati + 3hatj + hatk) and (3hati + hatj +2hatk) respectively, prove that DeltaABC is equilateral.