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If a =2hati+3hatj+4hatk and b =4hati+3ha...

If `a =2hati+3hatj+4hatk and b =4hati+3hatj +2hatk` ,find the angel between a and b.

Text Solution

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The correct Answer is:
A, B, C
`theta = cos^(-1) ((a.b)/(ab)).`
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Knowledge Check

  • If a = hati+2hatj-3hatk and b = 3hati-hatj+2hatk then the angle between the vectors a + b and a - b is

    A
    `60^@`
    B
    `90^@`
    C
    `45^@`
    D
    `55^@`

  • If a=2hati+2hatj-8hatk and b=hati+3hatj-4hatk , then the magnitude of a+b is equal to

    A
    `13`
    B
    `(13)/(5)`
    C
    `3/13`
    D
    `4/13`

  • If a= 7hati+hatj-4hatk , and b= 2hati+6hatj=3hatk , then the projection of a on b is

    A
    `32/7`
    B
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    C
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    D
    `8/sqrt66`

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