The vectors `vecA` has a magnitude of 5 unit `vecB` has a magnitude of 6 unit and the cross product of `vecA and vecB` has a magnitude of 15 unit. Find the angle between `vecA and vecB`.

Answer

A, C

Explanation

If the angle between A and B is `theta`, the cross product
will have a magnitude
`|AxxB| = AB sin theta`
or `15 = 5xx6 sin theta`
or `sin theta =(1)/(2)`
Thus, `theta = 30^@`
or `150^@`